10x^2-4x-2=8

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Solution for 10x^2-4x-2=8 equation:



10x^2-4x-2=8
We move all terms to the left:
10x^2-4x-2-(8)=0
We add all the numbers together, and all the variables
10x^2-4x-10=0
a = 10; b = -4; c = -10;
Δ = b2-4ac
Δ = -42-4·10·(-10)
Δ = 416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{416}=\sqrt{16*26}=\sqrt{16}*\sqrt{26}=4\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{26}}{2*10}=\frac{4-4\sqrt{26}}{20} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{26}}{2*10}=\frac{4+4\sqrt{26}}{20} $

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